A proton and an `alpha`-particle are accelerated, using the same potential difference. How are the de-Broglie wavelengths `lambda_(p) and lambda_(a)` related to each other?

Explanation

To find the relationship between the de-Broglie wavelengths of a proton (\( \lambda_p \)) and an alpha particle (\( \lambda_a \)) when both are accelerated through the same potential difference, we can follow these steps:

### Step 1: Understand the Kinetic Energy
When a charged particle is accelerated through a potential difference \( V \), its kinetic energy (\( KE \)) is given by:
\[ KE = qV \]
where \( q \) is the charge of the particle.
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