There are two sources of light, each emitting with a power of 100W. One emits X-rays of wavelength 1nm and the other visible light at 500nm. Find the ratio of number of photons of X-rays to the photons of visible light of the given wavelength?

Explanation

Here, `P=100W, lambda_(1)=1nm, lambda_(2)=500nm`
Let `n_(1),n_(2)`=no. of photons X-rays and visible light emitted from the two sources
`:. P=n_(1) (hc)/(lambda_(1)) = n_(2) (hc)/(lambda_(2)) or (n_(1))/(lambda_(1))=(n_(2))/(lambda_(2)) or (n_(1))/(n_(2))=(lambda_(1))/(lambda_(2))=1/500`