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Which law is violated in the following n...

Which law is violated in the following nuclear reaction? `._0n^1 to ._1H^1+._(-1)e^0`?

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AI Generated Solution

To determine which law is violated in the nuclear reaction \( _0n^1 \rightarrow _1H^1 + _{-1}e^0 \), we will analyze the conservation laws that apply to nuclear reactions. ### Step-by-Step Solution: 1. **Identify the Particles and Their Properties:** - On the left-hand side (LHS), we have a neutron \( _0n^1 \). - On the right-hand side (RHS), we have a proton \( _1H^1 \) and an electron \( _{-1}e^0 \). ...
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Knowledge Check

  • Statement-1: No law is violated in the nuclear reaction ._(0)n^(1)to._(1)H^(1)+._(-1)e^(0) Statement-2: Mass number and charge number, both are conserved

    A
    Statement-1 is true, Statement-2 is true and Statement-2 is correct explanation of Statement-1.
    B
    Statement-1 is true, Statement-2 is true, but Statement-2 is not a correct explanation of Statement-1.
    C
    Statement-1 is true, but Statement-2 is false
    D
    Statement-1 is false, but Statement-2 is true.

  • What is X in the following nuclear reaction? N_7^14 + H_1^1 to O_8^15 +X

    A
    `e_(+1)^@`
    B
    `n_0^1`
    C
    `gamma`
    D
    `e_(-1)^@`

  • Which is the missing particle in the following nuclear reaction ? ""_(3)Li^(7) + ""_(1)H^(2) rarr ""_(3)Li^(8) + ?

    A
    Proton
    B
    Deutron
    C
    positron
    D
    alpha- particle

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