Which law is violated in the following nuclear reaction? `._0n^1 to ._1H^1+._(-1)e^0`?
Text Solution
AI Generated Solution
To determine which law is violated in the nuclear reaction \( _0n^1 \rightarrow _1H^1 + _{-1}e^0 \), we will analyze the conservation laws that apply to nuclear reactions.
### Step-by-Step Solution:
1. **Identify the Particles and Their Properties:**
- On the left-hand side (LHS), we have a neutron \( _0n^1 \).
- On the right-hand side (RHS), we have a proton \( _1H^1 \) and an electron \( _{-1}e^0 \).
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