int(0)^(1)(e^(2x)-1)/(e^(2x)+1)dx=...

`int_(0)^(1)(e^(2x)-1)/(e^(2x)+1)dx=`

`log(e-(1)/(e ))`

`log(e+(1)/(e ))`

`log((1)/(e )-e)`

`log (1+e^(2))`

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The correct Answer is:

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