int(-pi//2)^(pi//2) x sin x cos x dx=...

`int_(-pi//2)^(pi//2) x sin x cos x dx=`

A

0

B

`(pi)/(2)`

C

`(pi)/(4)`

D

2

Text Solution

Verified by Experts

The correct Answer is:

C

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int_(-pi//2)^(pi//2) sin^(2) x cos^(2) x (sin x +cos x) dx =

A

`2//15`

B

`4//15`

C

`6//15`

D

`8//15`

int_(-pi//2)^(pi//2) sin^(2)x cos^(2) x(sin xcos x)dx=

A

`2//15`

B

`4//15`

C

`2//15`

D

0

Given that int_(0)^(pi//2) sin^(4) x cos^(2) x dx= (pi)/(32) , then int_(0)^(pi//2) cos^(4) x sin^(2) x dx =

A

`(pi)/(32)`

B

`(3pi)/(32)`

C

`(pi)/(2)`

D

none

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