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(dy)/(dx)coty=cos(x+y)+cos(x-y) A)lo...

`(dy)/(dx)coty=cos(x+y)+cos(x-y)` A)`log(secy+tany)=2cos x+c` B)`log(cosecy-coty)=2sinx+c` C)`log(cosy-coty)=2cosx+c` D)`cosy-coty=c.e^(cosx)`

A

`log(secy+tany)=2cos x+c`

B

`log(cosecy-coty)=2sinx+c`

C

`log(cosy-coty)=2cosx+c`

D

`cosy-coty=c.e^(cosx)`

Text Solution

Verified by Experts

The correct Answer is:
B
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