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e^(dy//dx)=x A)y=xlog((x)/(e))+c B)y=xlo...

`e^(dy//dx)=x` A)`y=xlog((x)/(e))+c` B)`y=xlogx+c` C)`y=e^(x)+c` D)`x=ylog(ex)+c`

A

`y=xlog((x)/(e))+c`

B

`y=xlogx+c`

C

`y=e^(x)+c`

D

`x=ylog(ex)+c`

Text Solution

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The correct Answer is:
A
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