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x cos^(2)ydx=ycos^(2)xdy A)xsin2y=ycos2...

`x cos^(2)ydx=ycos^(2)xdy` A)`xsin2y=ycos2x+c` B)`x tanx=ytany+c` C)`x tan x-y tan y=ln(secx/ sec y)+c` D)`x sec x=y sec y+c`

A

`xsin2y=ycos2x+c`

B

`x tanx=ytany+c`

C

`x tan x-y tan y=ln(secx/ sec y)+c`

D

`x sec x=y sec y+c`

Text Solution

Verified by Experts

The correct Answer is:
C
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