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x(logx-logy)dy-ydx=0, where logx-logy=u ...

`x(logx-logy)dy-ydx=0,` where `logx-logy=u` A)`cx=log(x/y)` B)`log.(x)/(y)=log(log.(x)/(y))-(x)/(y)=x+c` C)`e^((x)/(y))+e^((x)/(y)-1)=e^(x)+c` D)`u=c(logu-1)`

A

`cx=log(x/y)`

B

`log.(x)/(y)=log(log.(x)/(y))-(x)/(y)=x+c`

C

`e^((x)/(y))+e^((x)/(y)-1)=e^(x)+c`

D

`u=c(logu-1)`

Text Solution

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The correct Answer is:
A
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