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(dy)/(dx)tany=sinx+cosx...

`(dy)/(dx)tany=sinx+cosx`

A

`sinx+log(secy)=cosx+c`

B

`cosx-log(cosy)=sinx+c`

C

`cosx+log(cosy)=sinx+c`

D

`cosy+log(cosx)=siny+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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