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(dy)/(dx)-e^(x)=ye^(x), when x=0, y=1...

`(dy)/(dx)-e^(x)=ye^(x)`, when `x=0, y=1`

A

`log(1+y)=e^(x)+log2-1`

B

`log(2+y)=e^(x)+log2`

C

`logy=1+e^(x)log2`

D

`log(1+x)+e^(y)+log2=1`

Text Solution

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The correct Answer is:
A
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