Two spheres of masses `M_(1)` and `M_(2)` and separated by a distance d are situated in air and the gravitational force of attraction between them is F. If the two spheres are kept in a liquid of specific gravity 5 then the gravitational force between them will be

Options

A. 5 F
B. `(F)/(5)`
C. F
D. `sqrt(F)`

Explanation

To solve the problem, we need to analyze the gravitational force between two spheres of masses \( M_1 \) and \( M_2 \) separated by a distance \( d \) when they are in air and when they are submerged in a liquid of specific gravity 5.

### Step-by-Step Solution:

1. **Understanding Gravitational Force in Air**:
The gravitational force \( F \) between two masses \( M_1 \) and \( M_2 \) separated by a distance \( d \) in air is given by the formula:
\[ F = \frac{G M_1 M_2}{d^2} \]
where \( G \) is the universal gravitational constant.

2. **Effect of Specific Gravity**:
Specific gravity is a measure of the density of a substance compared to the density of water. A specific gravity of 5 means that the liquid is 5 times denser than water. However, the specific gravity of the liquid does not affect the gravitational force between the two masses directly.

3. **Gravitational Force in Liquid**:
When the two spheres are submerged in a liquid, the gravitational force between them remains the same because:
- The masses \( M_1 \) and \( M_2 \) do not change.
- The distance \( d \) between the centers of the two spheres does not change.
- The gravitational force depends only on the masses and the distance between them, not on the medium in which they are placed.

4. **Conclusion**:
Therefore, the gravitational force \( F' \) between the two spheres when they are submerged in the liquid remains:
\[ F' = \frac{G M_1 M_2}{d^2} = F \]

### Final Answer:
The gravitational force between the two spheres when kept in a liquid of specific gravity 5 is still \( F \).