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A mass of 1 kg is supended by a string. ...

A mass of 1 kg is supended by a string. It is
(i) lifted up with an acceleration `4.9 m//s^(2)`
(ii) lowered with an acceleration `4.9 m//s^(2)`
Then the ration of the tension in the string in the two cases is

A

`3 : 1`

B

`1 : 3`

C

`2 : 1`

D

`1: 2`

Text Solution

Verified by Experts

The correct Answer is:
A
`(T_(1))/(T_(2))=(m(g+a))/(m(g-a))=(9.8+4.9)/(9.8-4.9)=(3)/(1)`
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