Two bodies of equal masses situated at diametically opposite points go around a circle of radius R under the action of their mutual gravitational attraction. The speed (v) of each body is given by

Options

A. `sqrt((Gm)/(R ))`
B. `(1)/(2)sqrt((Gm)/(R ))`
C. `sqrt((4Gm)/(R ))`
D. `(1)/(2R)sqrt((1)/(Gm))`

Answer

B

Explanation

`(Gmm)/((2R)^(2))=(mv^(2))/(R )" " therefore v=(1)/(2)sqrt((Gm)/(R ))`