A research satellite of mass `200 kg` circles the earth in an orbit of average radius `3 R//2`, where `R` is the radius of the earth. Assuming the gravitational pull on the mass of `1 kg` on the earth's surface to be `10 N`, the pull on the satellite will be

Options

A. 890 N
B. 892 N
C. 889 N
D. 880 N

Answer

C

Explanation

`(g')/(g)=((R )/(R+h))^(2)=((R )/((3R)/(2)))^(2)=(4)/(9)`
`therefore g'=(4)/(9)g " " therefore w' = mg' = (4)/(9)(mg)`
`therefore` If the satellite is on the earth, then the gravitational pull
`= mg = 200xx10=2000 N`
`therefore` For the revolving satellite,
`therefore w'=(4)/(9) (mg)=(4)/(9)xx2000 = 889 N`