Assume that the acceleration due to gravity on the surface of the moon is `0.2` times the acceleration due to gravity on the surface of the earth. If `R_e` is the maximum range of a projectile on the earth's surface, what is the maximum range on the surface of the moon for the same velocity of projection

Options

A. `5R_(e )`
B. `0.2R_(e )`
C. `0.5R_(e )`
D. `2R_(e )`

Answer

A

Explanation

For the earth, maximum H.R. `= R_(e )=(v^(2))/(g_(e ))`
and for the moon, `R_(m)=(v^(2))/(g_(m))`
`therefore (R_(m))/(R_(e ))=(g_(e))/(g_(m))=(g_(e))/(0.2g_(e))=5`
`therefore R_(m)=5R_(e )`