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Two satellites of masses 80 kg and 120 k...

Two satellites of masses 80 kg and 120 kg revolve round a planet in circular orbits of radii 16 R and 9 R respectively, where R is radius of the planet. The ratio of the speeds of satellites will be

A

`(80)/(120)`

B

`(4)/(3)`

C

`(16)/(25)`

D

`(3)/(4)`

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The correct Answer is:
To find the ratio of the speeds of two satellites revolving around a planet, we can use the formula for orbital velocity. The orbital velocity \( V \) of a satellite in a circular orbit is given by: \[ V = \sqrt{\frac{GM}{R}} \] where: - \( G \) is the gravitational constant, - \( M \) is the mass of the planet, - \( R \) is the distance from the center of the planet to the satellite (which is the radius of the orbit). In this case, we have two satellites: 1. Satellite 1 (mass = 80 kg) at radius \( R_1 = 16R \) 2. Satellite 2 (mass = 120 kg) at radius \( R_2 = 9R \) ### Step 1: Calculate the orbital velocity for Satellite 1 Using the formula for orbital velocity: \[ V_1 = \sqrt{\frac{GM}{R_1}} = \sqrt{\frac{GM}{16R}} \] ### Step 2: Calculate the orbital velocity for Satellite 2 Similarly, for Satellite 2: \[ V_2 = \sqrt{\frac{GM}{R_2}} = \sqrt{\frac{GM}{9R}} \] ### Step 3: Find the ratio of the speeds of the satellites Now, we want to find the ratio \( \frac{V_1}{V_2} \): \[ \frac{V_1}{V_2} = \frac{\sqrt{\frac{GM}{16R}}}{\sqrt{\frac{GM}{9R}}} \] ### Step 4: Simplify the ratio The \( GM \) and \( R \) terms cancel out: \[ \frac{V_1}{V_2} = \frac{\sqrt{1/16}}{\sqrt{1/9}} = \frac{\frac{1}{4}}{\frac{1}{3}} = \frac{3}{4} \] ### Conclusion Thus, the ratio of the speeds of the satellites is: \[ \frac{V_1}{V_2} = \frac{3}{4} \]

To find the ratio of the speeds of two satellites revolving around a planet, we can use the formula for orbital velocity. The orbital velocity \( V \) of a satellite in a circular orbit is given by: \[ V = \sqrt{\frac{GM}{R}} \] where: - \( G \) is the gravitational constant, ...
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MARVEL PUBLICATION-GRAVITATION -TEST YOUR GRASP -2
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