The satellite of mass m revolving in a circular orbit of radius r around the earth has kinetic energy E. then, its angular momentum will be

Options

A. `sqrt(2Emr)`
B. `sqrt(2Emr^(2))`
C. `sqrt((E )/(mr^(2)))`
D. `(E )/(2mr^(2))`

Answer

B

Explanation

`E=(1)/(2)mv^(2) " " therefore 2E = mv^(2) " " therefore 2Em = m^(2)v^(2)`
`therefore` Linear momentum `(p)=mv=sqrt(2Em) " "` ….(1)
`therefore` Angular momentum (L) of the satellite
`= mvr = sqrt(2Em). R = sqrt(2Emr^(2))`