For a satellite the escape velocity is 1...

For a satellite the escape velocity is 11km/s. If the satellite is launched at an angle of `30^(@)` with the vertical, then the escape velocity will be

`11sqrt(3)km//s`

`11km//s`

`5.5km//s`

`(11)/(sqrt(3))km//s`

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The correct Answer is:

Escape velocity does not depend upon the angle of projection. [11 km/s]

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