Find the percentage decrease in the weight of the body when taken to a depth of `32 km` below the surface of earth. Radius of the earth is `6400 km`.

Options

A. 0.01
B. 0.0075
C. 0.005
D. 0.0025

Answer

C

Explanation

`mg'=mg(1-(x)/(R ))=mg(1-(32)/(6400))=mg((199)/(200))`
`therefore mg-mg'=(1)/(200)g`
`therefore` Percentage decrease in weight `= (mg-mg')/(mg)xx100`
`=(1)/(200)(g)/(g)xx100=(1)/(2)=0.5%`