The linear speed of a particle at the equator of the earth due to its spin motion is V . What is its linear speed latitude `60^(@)`?

Options

A. 2V
B. `(V)/(2)`
C. `(2)/(sqrt(3))`
D. `(sqrt(3))/(2)`

Answer

B

Explanation

The particle on the equator of the earth moves in a circle of radius R, so that `V = R omega`.
At latitude of `60^(@)`, it moves in a circle of smaller radius r, where `r = R cos 60^(@)=(R )/(2)`
`therefore` Linear velocity of the particle `V'=r omega = (R )/(2)omega`
`therefore V'=(V)/(2)`