Home
Class 12
PHYSICS
Time period of pendulum, on a satellite ...

Time period of pendulum, on a satellite orbiting the earth, is

A

T

B

2T

C

zero

D

infinite

Text Solution

Verified by Experts

The correct Answer is:
D

`g=0 " " therefore T = 2pi sqrt((l)/(g))to oo`
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP -2|20 Videos
  • ELECTROSTATICS

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|20 Videos
  • INTERFERENCE AND DIFFRACTION

    MARVEL PUBLICATION|Exercise TEST YOUR GRASP|20 Videos

Similar Questions

Explore conceptually related problems

Assertion : The time period of a pendulum on a satellite orbiting the earth in infinite Reason:The period of a pendulum is inversely propotional to square root of acceleration due to gravity

Assertion : The time-period of pendulu, on a satellite orbiting the earth is infinity . Reason : Time-period of a pendulum is inversely proportional to sqrt(g) .

Statement-1: The time period of a simple pendulum on a satellite orbiting the earth is infinity Because Statement-2: Effective value of g in orbiting satellite is zero and T = 2pi sqrt((l)/(g))

Time period of a simple pendulum inside a satellite orbiting earth is

Assertion : A simple pendulum inside a satellite orbiting the earth has an infinite time period . Reason : Time period of simple pendulum varies inversely with sqrtg

Calculate the orbital velocity and time period of revolution of a satellite orbiting around the earth at a distance of 3,000 km.

The period of revolution of a satellite orbiting Earth at a height 4R above the surface of Warth is x hrs, where R is the radius of earth. The period of another satellite at a height 1.5R from the surface of the Earth is

Calculate the period of revolution of a satellite orbiting above the surface of the Earth at a distance equal to 9 times the radius of the Earth.

The time period of a simple pendulum at the centre of the earth is

MARVEL PUBLICATION-GRAVITATION -TEST YOUR GRASP -2
  1. Time period of pendulum, on a satellite orbiting the earth, is

    Text Solution

    |

  2. A body weights 72 N on the surface of the earth. What is the gravitati...

    Text Solution

    |

  3. What would be the acceleration due to gravity on the surface of a plan...

    Text Solution

    |

  4. The acceleration due to gravity on the moon is 1//6th of that on the e...

    Text Solution

    |

  5. The weight of a man in a lift moving upwards with an acceleration 'a' ...

    Text Solution

    |

  6. If there would have been a smaller gravitational effect, then which on...

    Text Solution

    |

  7. The orbital velocity of an artifical satellite in a circular orbit jus...

    Text Solution

    |

  8. If rho is the mean density of the earth and R is its radius, then the ...

    Text Solution

    |

  9. A planet revolves in an elliptical orbital around the sun. The kinetic...

    Text Solution

    |

  10. What would be the duration of the year, if the distance between the ea...

    Text Solution

    |

  11. If the potential energy of a body at a height h from the surface of th...

    Text Solution

    |

  12. An artificial satellite of mass 200 kg, revolves around the earth in a...

    Text Solution

    |

  13. A body is projected upwards with a velocity of 4 xx 11.2 "km s"^(-1) f...

    Text Solution

    |

  14. In a satellite if the time of revolution is T, then kinetic energy is ...

    Text Solution

    |

  15. The acceleration due to gravity at the pols and the equator is g(p) an...

    Text Solution

    |

  16. Two persons A and B are trying to measure the value of acceleration du...

    Text Solution

    |

  17. At what height from the surface of earth will the value of g be reduce...

    Text Solution

    |

  18. The depth d, at which the value of acceleration due to gravity becomes...

    Text Solution

    |

  19. A satellite is orbiting around the earth at a mean radius of 16 times ...

    Text Solution

    |

  20. The radius of the earth is 6400 km and g=10m//sec^(2). In order that a...

    Text Solution

    |

  21. For a planet, the graph of T^(2) against r^(3) is plotted. The slope o...

    Text Solution

    |