The dimensions of universal gravitational constant are :-

Options

A. `[L^(1)M^(0)T^(0)]`
B. `[L^(2)M^(1)T^(0)]`
C. `[L^(-1)M^(1)T^(-2)]`
D. `[L^(3)M^(-1)T^(-2)]`

Answer

D

Explanation

`F=G(m_(1)m_(2))/(r^(2))" " therefore G = (Fr^(2))/(m_(1)m_(2))`
Unit of `G-Nm^(2)//kg^(2)`
and Dimensional equation of G is
`[G]=[(Fr^(2))/(m_(1)m_(2))]=[(M^(1)L^(1)T^(-2)xxL^(2))/(M^(2))]`
`therefore [G] = [M^(-1)L^(3)T^(-2)]`