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If the potential energy of a body at a h...

If the potential energy of a body at a height h from the surface of the earth is `(mgR)/(2)`, then

A

h = 2R

B

`h = (R )/(2)`

C

`h = (R )/(3)`

D

h = R

Text Solution

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The correct Answer is:
D

`P.E.=-(GMm)/(R+h)=(-gR^(2)m)/(R+h)`
In magnitude, `(gR^(2)m)/(R+h)=(1)/(2)mgR`
`therefore R + h=2R " " therefore h = R`
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