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An artificial satellite of mass 200 kg, ...

An artificial satellite of mass 200 kg, revolves around the earth in an orbit of average radius 6670 km. What is its orbital kinetic energy ? `[M_("earth")=6xx10^(24)kg, G=6.67xx10^(-11)N-m^(2)//kg^(2)]`

A

`3xx10^(9)` joule

B

`6xx10^(9)` joule

C

`9xx10^(9)` joule

D

`7.5xx10^(9)` joule

Text Solution

Verified by Experts

The correct Answer is:
B
`K.E. = (GMm)/(2r)`
`= (6.67xx10^(-11)xx6xx10^(24)xx200)/(2xx6670xx10^(3))=6xx10^(9)J`
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Knowledge Check

  • If a satellite of mass 400 kg revolves around the earth in an orbit with speed 200 m/s then its potential energy is

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    `-1.2 ` MJ
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