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Green light of wavelength 5460Å is inci...

Green light of wavelength 5460Å is incident on an air glass interface. If the refractive index of glass is 1.5, the wavelength of light in glass would be `(C=3 xx 10^(8) ms^(-1))`n

A

`3640Å`

B

`5460Å`

C

`4861Å`

D

`6240Å`

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The correct Answer is:
To find the wavelength of green light in glass, we can use the relationship between the wavelength in air and the wavelength in a medium with a refractive index. Here are the steps to solve the problem: ### Step-by-Step Solution: 1. **Identify Given Values:** - Wavelength of green light in air, \( \lambda_a = 5460 \, \text{Å} \) (angstroms). - Refractive index of glass, \( n = 1.5 \). 2. **Understand the Relationship:** The relationship between the wavelength in air (\( \lambda_a \)) and the wavelength in glass (\( \lambda_g \)) is given by the formula: \[ \lambda_g = \frac{\lambda_a}{n} \] where \( n \) is the refractive index of the medium (glass in this case). 3. **Substitute the Values:** Substitute the known values into the formula: \[ \lambda_g = \frac{5460 \, \text{Å}}{1.5} \] 4. **Calculate the Wavelength in Glass:** Perform the division: \[ \lambda_g = \frac{5460}{1.5} = 3640 \, \text{Å} \] 5. **Final Answer:** The wavelength of light in glass is \( \lambda_g = 3640 \, \text{Å} \). ### Summary: The wavelength of green light in glass is \( 3640 \, \text{Å} \). ---

To find the wavelength of green light in glass, we can use the relationship between the wavelength in air and the wavelength in a medium with a refractive index. Here are the steps to solve the problem: ### Step-by-Step Solution: 1. **Identify Given Values:** - Wavelength of green light in air, \( \lambda_a = 5460 \, \text{Å} \) (angstroms). - Refractive index of glass, \( n = 1.5 \). ...
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MARVEL PUBLICATION-WAVE THEORY OF LIGHT AND POLARISATION -TEST YOUR GRASP -10
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