Polarising angle for water is ` 53^@4'`. If light is incident at this angle on the surface of water and reflected , the angle of refraction is

Options

A. `53^(@)4'`
B. `126^(@)56'`
C. `36^(@)56'`
D. `30^(@)4'`

Answer

C

Explanation

i=r `:.` Angle of reflection =`53^(@)4'`
and since the reflected and refracted rays are perpendicular to each other , when ther ray is incident at the polarising angle.
`:. 53^(@)4'+90^(@)+r'=180^(@)`
`:. r'=90^(@)-53^(@)4'=36^(@)56'`