An alternating e.m.f. is given by `E=E_(0) sin omega t`. In what time the e.m.f. will have half its maximu value, if E starts from zero?

Options

A. A. `T/4`
B. B. `T/8`
C. C. `T/12`
D. D. `T/16`

Answer

C

Explanation

`(E_0)/(2) = E_(0) sin((2 pit)/(T)) :. 1/2 = sin (pi)/6 = sin (2 pi t)/T`
`:. (2 pi t)/(T) = (pi)/6 :. T = T/12`.