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In a reverse biased diode, when the appl...

In a reverse biased diode, when the applied voltage changes by `1V`, the current is found to change by `0.5muA`. The reversebiase resistance of the diode is

A

`2xx10^5 Omega`

B

`2xx10^6 Omega`

C

`200 Omega`

D

`2 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`R=(DeltaV)/(DeltaI)=1/(0.5xx1^(-6)) = 10^6/(1//2)=2xx10^6 Omega`
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