In the given circuit
The current through the battery is

Options

A. 0.5 A
B. `1A`
C. `1.5A`
D. `2A`

Answer

C

Explanation

No current will flow through `D_2` because it is reverse biased . The diodes are assumed to be ideal and hence diode resistance are zero.
The equivalent circuit is shown below .

The equivalent resistances of parallel resistance of `20 Omega` and (5+5=10 `Omega`) is
`R_"eq" =(20xx10)/(20+10)=200/30 = 20/3 Omega`
`therefore` The current through the battery
`I=(10 V)/(20//3) =(10xx3)/20 =1.5` A