The circuit shown in figure (1) Contains two diodes each with a forward resistance of `50 ohm` and with infinite reverse resistance. If the battery voltage is `6 V`, the current through the `100 ohm` resistance is.
.

Options

A. zero
B. 0.02A
C. 0.03A
D. 0.036A

Answer

B

Explanation

In the given circuit, the diode `D_1` is forward biasd while the diode `D_2` is reverse biased. No current will flow through `D_2` because it has infinite backward resistance.
`therefore` As `D_1` has a forward resistance of 50 `Omega`, the total series resistance in the circuit (R')
`=50 Omega + 150 Omega + 100 Omega = 300 Omega`
`therefore ` Current `I=V/(R')=6/300=0.02 A`
`therefore` The current through `100 Omega` resistance = 0.02 A