A zener diode has a contract potential of `0.8 V` in the absence of biasing. It undergoes zener breakdown for an electric field of `10^(6) Vm^(-1)` at the depletion region of p-n junction. If the width of the depletion region is 2.4mu m, what should be the reverse biased potential for the zener breakdown to occur?

Options

A. 3.5 V
B. 2.5 V
C. 1.5 V
D. 0.5 V

Answer

B

Explanation

`E="dV"/"dx"`
`therefore dV=Edx = 10^6 V/m xx2.5xx10^(-6)`
`therefore dV=2.5` V
`therefore ` Breakdown voltage = 2.5 V