A transistor connected in CE mode , has a current gain of 50. If the load resistance is 5 K, input resistance is 1 K and the input peak voltage is 0.4 V, then the peak output voltage will be

Options

A. 25 V
B. 50 V
C. 75 V
D. 100 V

Explanation

To solve the problem step by step, we will follow the given parameters and apply the relevant formulas for a transistor in common emitter (CE) mode.

### Step 1: Identify the given parameters
- Current gain (β) = 50
- Load resistance (RL) = 5 kΩ = 5 × 10³ Ω
- Input resistance (RI) = 1 kΩ = 1 × 10³ Ω
- Input peak voltage (Vi) = 0.4 V

### Step 2: Calculate the voltage gain (AV)
The voltage gain (AV) for a common emitter transistor can be calculated using the formula:
\[ A_V = \beta \times \frac{R_L}{R_I} \]

Substituting the values:
\[ A_V = 50 \times \frac{5 \times 10^3}{1 \times 10^3} \]
\[ A_V = 50 \times 5 = 250 \]

### Step 3: Calculate the peak output voltage (Vo)
The output voltage (Vo) can be calculated using the formula:
\[ V_o = A_V \times V_i \]

Substituting the values:
\[ V_o = 250 \times 0.4 \]
\[ V_o = 100 \, \text{V} \]

### Final Answer
The peak output voltage (Vo) is **100 V**.

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