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In a n-p-n transister circuit the collec...

In a n-p-n transister circuit the collector current is `9 mA`. If `90%` of the electrons emitted reach the collector, find emitter current and base current

A

the base current is 10 mA

B

the emitter current is 1 mA

C

`alpha`=0.9 and `beta` = 9

D

`alpha` = 0.99 and `beta` =99

Text Solution

Verified by Experts

The correct Answer is:
C
`I_C=90/100 I_E " " therefore I_E= 10/9xx9` = 10 mA
`I_b=I_E-I_C = 1 mA`
`therefore alpha = I_C/I_E=0.9` and `beta=I_C/I_B= 0.9/0.1 = 9`
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