Consider an `n-p-n` transistor amplifer in common-emitter configuration. The current gain of the transistor is `100`. If the collector current changes by `1mA`, what will be the change in emitter current?

Options

A. 1.00mA
B. 0.99 mA
C. 1.01 mA
D. 1.5 mA

Answer

C

Explanation

`beta_"ac"=(DeltaI_C)/(DeltaI_b) = (DeltaI_C)/(DeltaI_E-DeltaI_C)`
`therefore 100=1/(DeltaI_E-1)`
`therefore DeltaI_E-1=1/100=0.01`
`therefore DeltaI_E`=1+0.01 = 1.01 mA