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A transistor is used in Common-emitter m...

A transistor is used in Common-emitter mode in an amplifier circuits. When a signal of 20 mV is added to the base-emitter voltage, the base current changes by `40 muA` and the collector current changes by 2mA. The load resistance is `5 kOmega` then the voltage gain is

A

15

B

20

C

5

D

10

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaV_"BE"=20 mV= 20 xx 10^(-3) V, R= 5xx10^3 Omega`
`beta=(DeltaI_b)/(DeltaI_b) = (2xx10^(-3))/(20xx10^(-6))`=100
Voltage gain = `V_o/V_i=(DeltaI_c xx R)/(DeltaV_"BE")`
`=(2xx10^(-3)xx5xx10^3)/(20xx10^(-3))` = 500
`therefore` Resistance gain = `"Voltage gain"/"Current gain" = 500/100`=5
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