If `alpha and beta` are the current gain in the CB and CE configurations respectively of the transistor circuit, then `(beta-alpha)/(alphabeta)=`

Options

A. 2
B. 1
C. 0.5
D. 1.5

Answer

B

Explanation

`beta=alpha/(1-alpha)`
`therefore beta-alpha=alpha/(1-alpha)-alpha`
`=(alpha-alpha +alpha^2)/(1-alpha ) =alpha^2/(1-alpha)` and `alphabeta=(alpha alpha)/(1-alpha)=alpha^2/(1-alpha)`
`therefore (beta-alpha)/(alphabeta)=(alpha^2/(1-alpha))xx((1-alpha)/alpha^2)=1`