In the following common emitter configuration an n-p-n transistor with current gain `beta` = 100 is used. The output voltage of the amplifier will be

Options

A. 10 mV
B. 0.1 V
C. 1.0 V
D. 10 V

Answer

C

Explanation

Output voltage = Input voltage `(V_i) xx` Voltage gain
`therefore V_o=V_i` x (Current gain ) x (Resistance gain) …(1)
Current gain =`beta`=100
Resistance gain = `(10xx10^3)/(1xx10^3)`=10
`V_i=10^(-3)V ` = 1 mV
`therefore` From (1) , `V_o=10^(-3) xx 100 xx 10 `= 1V