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In common base circuit of a transistor ,...

In common base circuit of a transistor , current amplification factor is `0.95`. Calculate the emitter current , if base current is `0.2` mA

A

2 mA

B

4 mA

C

6 mA

D

8 mA

Text Solution

Verified by Experts

The correct Answer is:
B
`alpha=0.95 = I_C/I_E` and `I_E=I_C-I_B " " therefore I_C=I_E+I_B`
`therefore I_C=0.95 I_E`
Thus `I_E+I_B=0.95I_E`
`therefore I_E(1-0.95) = -I_B`
`therefore I_E(5/100)=2/10 mA ` (-ve sign neglected)
`50I_E=200 " " therefore I_E=4mA`
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