In the following circuit, the output `Y` for all possible inputs `A` and `B` is expressed by the truth table:

Options

A.
B.
C.
D.

Answer

C

Explanation

Here both (1) and (2) are NOR gates.
For gate I, output = `bar(A+B)`
This acts as input for gate (2) .
The final output is `Y=barbar(A+B) = A+B`
This is the Boolean expression of OR gate.
Thus the circuit acts as an OR gate and its truth table is
This is given in (c )