A small hole is made in a disc of mass `M` and radius `R` at a distance `R//4` from centre. The disc is supported on a horizontal peg through this hole. The moment of inertia of the disc about horizontal peg is

Options

A. `MR^(2)//2`
B. `5MR^(2)//16`
C. `9MR^(2)//16`
D. `5MR^(2)//4`

Answer

C

Explanation

`I_(o)=I_(c )+MR^(2)`
`= (MR^(2))/(2)+(MR^(2))/(16)`
`=(9)/(16)MR^(2)`