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The moment of inertia of a ring about it...

The moment of inertia of a ring about its geometrical axis is I, then its moment of inertia about its diameter will be

A

1 I

B

I/2

C

I

D

I/4

Text Solution

Verified by Experts

The correct Answer is:
B
`I_(d)= (I_(c ))/(2)=(I)/(2)`.
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