The M.I. of a wheel of mass 8 kg and radius of gyration 25 cm is

Options

A. `5 kg m^(2)`
B. `1.5 kg m^(2)`
C. `2.5 kg m^(2)`
D. `0.5 kg m^(2)`

Answer

D

Explanation

`I = mK^(2) = 8xx(0.25)^(2)= 8xx((1)/(4))^(2)`
`= 8xx(1)/(16)=(1)/(2)=0.5 kg m^(2)`
`I = 0.5 kg m^(2)`