If a flywheel of mass m kg and radius r m is revolving at n rps, then the kinetic energy of rotation will be

Options

A. `pi^(2)n^(2)m^(2)r^(2)`
B. `pi^(2)n^(2)m^(2)r`
C. `pi^(2)n^(2)m r^(2)`
D. `pi^(2)n m^(2)r^(2)`

Answer

C

Explanation

`K.E. = (1)/(2) I omega^(2)=(1)/(2)(mR^(2))/(2)xx 4pi^(2)n^(2)`