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The radius of gyration of flywheel is (3...

The radius of gyration of flywheel is `(3//pi)m` and its mass is 1 kg. If the speed of the flywheel is changed from 20 rpm to 60 rmp, then the work done would be

A

16 J

B

12 J

C

24 J

D

32 J

Text Solution

Verified by Experts

The correct Answer is:
A

Work done = Change in K.E.
`K.E. = (1)/(2)I (omega_(2)^(2)-omega_(1)^(2))`
`=(1)/(2)m k^(2)4 pi^(2)(n_(2)^(2)-n_(1)^(2))`
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