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A fly wheel of M.I. 0.32 kg m^(2) is rot...

A fly wheel of M.I. `0.32 kg m^(2)` is rotated steadily at 120 rad/s by 50 w electric motor. Then the value of the frictional couple opposing rotation is,

A

4.2 Nm

B

0.42 Nm

C

0.042 Nm

D

42 Nm

Text Solution

Verified by Experts

The correct Answer is:
B
`P = tau omega`
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