If a wheel has mass 70 kg and radius of gyration 1 m, then the torque required an angular 1 m, then the torque required an angular acceleration of `"2 rev"//s^(2)` will be

Options

A. `140 pi Nm`
B. `380 pi Nm`
C. `180 pi Nm`
D. `280 pi Nm`

Answer

D

Explanation

`tau = I alpha = mk^(2) alpha " here " alpha =2xx2 pi rad//s^(2)`