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A wheel of mass 40 kg and radius of gyra...

A wheel of mass 40 kg and radius of gyration 0.5 m comes to rest from a speed of 180 rpm in 30 s assuming that the retardation is uniform then the value of the retarding torque, in Nm will be

A

`1 pi`

B

`3 pi`

C

`2 pi`

D

`4 pi`

Text Solution

Verified by Experts

The correct Answer is:
C
`tau = I alpha = M k^(2) alpha`.
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