If a particle of mass 1 gm is moving along a circular path of radius 1 m with a velocity of 1 m/s, then the its angular momentum is

Options

A. `1 kg m^(2)//s`
B. `10^(-2)kg m^(2)//s`
C. `10^(-2) kg m^(2)//s`
D. `10^(-1)kg m^(2)//s`

Answer

B

Explanation

L = mrv
`= 10^(-3)xx1xx1`
`= 10^(-3)kg m^(2)//s`.