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A particle performing uniform circular motion gas angular momentum `L`. If its angular frequency is double and its kinetic energy halved, then the new angular momentum is :

A

4L

B

0.5L

C

2L

D

0.25L

Text Solution

Verified by Experts

The correct Answer is:
D

`E_(1)=(1)/(2)I_(1)omega_(1)^(2)=(1)/(2)L_(1)omega_(1)`
`E_(2)=(1)/(2)I_(2)omega_(2)^(2)=(1)/(2)L_(2)omega_(2)`
`therefore (L_(2))/(L_(1))=(E_(2))/(E_(1))xx(omega_(1))/(omega_(2))`
`therefore L_(2)=(L_(1))/(4)=0.25 L`
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